2w^2+3w=78

Solution for 2w^2+3w=78 equation:

2w^2+3w=78

We move all terms to the left:

2w^2+3w-(78)=0

a = 2; b = 3; c = -78;
Δ = b2-4ac
Δ = 32-4·2·(-78)
Δ = 633
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{633}}{2*2}=\frac{-3-\sqrt{633}}{4}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{633}}{2*2}=\frac{-3+\sqrt{633}}{4}
$